(x^2-3x+2)(x-5)=0

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Solution for (x^2-3x+2)(x-5)=0 equation: 


Simplifying
(x2 + -3x + 2)(x + -5) = 0

Reorder the terms:
(2 + -3x + x2)(x + -5) = 0

Reorder the terms:
(2 + -3x + x2)(-5 + x) = 0

Multiply (2 + -3x + x2) * (-5 + x)
(2(-5 + x) + -3x * (-5 + x) + x2(-5 + x)) = 0
((-5 * 2 + x * 2) + -3x * (-5 + x) + x2(-5 + x)) = 0
((-10 + 2x) + -3x * (-5 + x) + x2(-5 + x)) = 0
(-10 + 2x + (-5 * -3x + x * -3x) + x2(-5 + x)) = 0
(-10 + 2x + (15x + -3x2) + x2(-5 + x)) = 0
(-10 + 2x + 15x + -3x2 + (-5 * x2 + x * x2)) = 0
(-10 + 2x + 15x + -3x2 + (-5x2 + x3)) = 0

Combine like terms: 2x + 15x = 17x
(-10 + 17x + -3x2 + -5x2 + x3) = 0

Combine like terms: -3x2 + -5x2 = -8x2
(-10 + 17x + -8x2 + x3) = 0

Solving
-10 + 17x + -8x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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